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Message #02645
Re: Stokes with viscosity, revisited
On Tue, May 30, 2006 at 10:07:47AM +0000, Alexander Jarosch wrote:
> Hi everybody.
>
> There was a short discussion about Stokes flow on complex geometries. I
> would like to report that a ffc form like the one below works well on
> complex geometries, I still only have a factor of 1.2 offset in
> magnitude if I compare it with another fem model. I would like to get
> some feedback about this form, whether it is okay or not from the
> developers point of view.
>
> much appreciated,
>
> Alex
>
> ffc form -------------------
>
> scalar = FiniteElement("Lagrange", "triangle", 1)
> vector = FiniteElement("Vector Lagrange", "triangle", 1)
> system = vector + scalar
>
> (v, q) = TestFunctions(system)
> (u, p) = TrialFunctions(system)
>
> f = Function(vector)
> h = Function(scalar)
> nu = Function(scalar)
>
> beta = 0.2
> delta = beta*h*h
>
> a = (nu*dot(grad(v), grad(u)) - div(v)*p + nu*q*div(u) +
> delta*dot(grad(q), grad(p)))*dx
> L = dot(v + mult(delta, grad(q)), f)*dx
I think it looks a little strange. The difference from what you had
before seems to be that you have included the viscosity in the
incompressibility term:
nu*q*div(u)
Is this what makes the difference? If so, I don't know why this
helps. It's certainly ok to put it there since you're solving for
div(u) = 0 anyway, so nu*div(u) = 0 is also correct.
In some way, it corresponds to a smaller penalty for compressibility
when the viscosity is small which might be reasonable.
/Anders
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