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[Ted Kord <question96571@xxxxxxxxxxxxxxxxxxxxx>]

New question #96571 on DOLFIN:
https://answers.launchpad.net/dolfin/+question/96571

Hi

I'm attempting to solve the following problem (using the C++ interface):

du/dt - div grad u = f(u)

Due to the non-linearity associated with f(u), I am using the parameters at time t to calculate it thus avoiding the use of a nonlinear root-finding algorithm.

The problem I have is how to define f(u).

Say, f(u) is:
      0.1/(1 + exp(u - 2) )

How do obtain the scalar value 'u' to pass as the argument to f(u) at every time step.

Thanks.

Ted

 

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