dolfin team mailing list archive

[Johan Hake <johan.hake@xxxxxxxxx>]

On Monday 08 February 2010 13:41:29 Anders Logg wrote:
> On Mon, Feb 08, 2010 at 01:35:16PM -0800, Johan Hake wrote:
> > On Monday 08 February 2010 01:15:12 Anders Logg wrote:
> > > On Sun, Feb 07, 2010 at 11:25:28PM +0000, Garth N. Wells wrote:
> > > > Anders Logg wrote:
> > > > > On Sun, Feb 07, 2010 at 10:58:44PM +0000, Garth N. Wells wrote:
> > > > >> Anders Logg wrote:
> > > > >>> This looks a like a non-optimal solution. Are you returning the
> > > > >>> mesh by value? That will lead to creation of a temporary and
> > > > >>> copying of the entire refined mesh.
> > > > >>
> > > > >> So they used say ;). Apparently modern compilers are all clever
> > > > >> enough not to.
> > > > >>
> > > > >> Garth
> > > > >
> > > > > Is that really so? Do you have any good references that explain
> > > > > this in detail?
> > > >
> > > >   http://en.wikipedia.org/wiki/Return_value_optimization
> > > >
> > > > and from 'man gcc'
> > > >
> > > > -fno-elide-constructors
> > > >   The C++ standard allows an implementation to omit creating a
> > > > temporary which is only used to initialize another object of the same
> > > > type. Specifying this option disables that optimization, and forces
> > > > G++ to call the copy constructor in all cases.
> > >
> > > ok, seems correct. I tried the following piece of code with some
> > > debugging added to the copy constructor and assignment operator in
> > > class Mesh:
> > >
> > >   Mesh refined_mesh_1 = UniformMeshRefinement::refine(mesh);
> > >
> > >   Mesh refined_mesh_2;
> > >   refined_mesh_2 = UniformMeshRefinement::refine(mesh);
> > >
> > > The first refinement does not lead to any call to either of the copy
> > > constructor or assignment operator.
> > >
> > > The second call leads to one call to the assignment operator.
> > >
> > > This is expected but means we need to be careful with how the
> > > refinement is called (on the same line as initialization).
> > >
> > > Should we have a look and see if there are other places where we could
> > > return by value?
> >
> > The operator* and operator+ were explicitly not included because they
> > needed to be implemented as a return by value method. Now they can be
> > added in the same way as the Python equivalents I think.
> 
> You mean in the linear algebra interface?

Yes.

Johan