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[Anders Logg <logg@xxxxxxxxx>]

There seems to be a problem with the new approach to mesh refinement
(return by value).

Try the following simple test (in Python):

  mesh = UnitSquare(3, 3)
  new_mesh = refine(mesh)

This generates the following output:

  Mesh empty constructor: this = 11fb880
  Mesh empty constructor: this = c03f63c0
  Calling uniform refinement free function: mesh = 11fb880
  Mesh empty constructor: this = c03f6160
  Mesh assignment operator: this = c03f63c0
  Mesh destructor: this = c03f6160
  Mesh copy constructor: this = 21eefb0
  Mesh assignment operator: this = 21eefb0
  Mesh destructor: this = c03f63c0
  Mesh destructor: this = 21eefb0
  Mesh destructor: this = 11fb880

I would have expected to see two constructors, two destructors and
zero copy constructors, but one extra mesh seems to be created.

--
Anders

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