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Re: mixed formulation

 

I'm not sure I follow your notation completely, but no you can't write something in FFC that is the product of two integrals. You need to compute each integral separately (or find a clever way to rewrite it as a single integral over the domain).

/Anders

Alessio Quaglino wrote:
I was confusing with the notation not distinguishing between S as a
function or as its coefficients. What I'm thinking is to write first the
unknowns S and u using the basis functions (indicated with the name of the
test function belonging to the same space):

S = S_coeff psi_trial
u = u_coeff phi_trial

so that we have:

A = dot(S, grad(phi)) =
= S_coeff (psi_trial, grad(phi)) =
= dot(u, psi) * (psi_trial, grad(phi)) =
= u_coeff * dot(phi_basis, psi) * (basis_psi, grad(phi))

the problem is that the two terms have first to be integrated and then
multiplied. Would that be possible?

Thanks,
Alessio


I don't see how to do this. As I understand, you have two matrices and
you want to compute their product. So you want to compute a sum of
products of integrals. I don't know how to write this as a single
integral (other than as a "double integral" over the square of the
domain).

What is the quantity you want to compute in the end? Can you write it as
a single integral?

/Anders


Alessio Quaglino wrote:
I have a question about matrix multiplication in FFC. Say I want to
measure a certain quantity S in respect to a test function psi belonging
to the same finite space:

S = dot(u, psi) (1)

and then I want to use this measure to assemble the bilinear form where
phi is taken from the same finite space of u:

A = dot(S, grad(phi)) (2)

this is equivalent to assemble the bilinear form (1) obtaining the "m x
n"
matrix S and then the bilinear form (2) obtaining the "n x m" matrix A.
Then what I need is to perform the multiplication A*S getting a "n x n"
matrix. Can I write A in such a way that this is done directly in the
form? Do I have to define a trilinear form?

Thanks,
Alessio Quaglino




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