I disagree! I think that this in some sense returns us to the previous objection with this method of
defining the coordinates, in that it is a circular definition. What I recommend for standardizing this (and
the completion of what I've done so far with it) is attaching the coordinate function not to the cell, but to
the measure on the integral. It could be done using the existing metadata functionality. This would look
something like:
coords = Function(iso_vector)
a = dot(grad(u), grad(v)*dx(0, {"coordinate_function" : coords})
or:
coords = Function(iso_vector)
a_t = dot(grad(u), grad(v))
a = a_t*dx(0) + a_t*dx(1, {"coordinate_function" : coords})
Which would allow for both an isoparametric and affine parts of the domain as separate integrals, but would
allow the same test, trial, and coefficients to exist for both. This would allow one to treat curved
boundaries and non-curved interiors, and is totally general -- if you want part of your form to be radial or
parabolic, you could do it. This is basically what I'm doing right now, only I've had to devise ways around
the present system by first inverting the affine jacobian and then applying the isoparametric jacobian. I
apply this with the form transformation machinery. Also, the facet integral would have to be rewritten to
accomodate a full transformation rather than what is done now. I've gotten around this as well, but it took
some work. No offense, but it seems to need a rewrite anyways, especially for the optimization. (I had it
eat all my memory and die when I tried to turn on optimization on a facet integral that involved a tensor.)
I'm totally willing to sift through FFC to do this, but I sort of need to know where to start. Kristian, any
hints? (oh, and I still am looking at the quadrature stuff, but it's been a busy summer for me here at KTH.
:) )
- Peter
On Sun, Aug 23, 2009 at 9:55 AM, Shawn Walker <walker@xxxxxxxxxxxxxxx> wrote:
On Sun, 23 Aug 2009, Kristian Oelgaard wrote:
> Quoting Shawn Walker <walker@xxxxxxxxxxxxxxx>:
>
>> Hello. I would like to know how hard it would be to modify FFC (and UFL)
>> to do the following.
>>
>> Here is the sample .ufl file:
>>
>> Poisson.ufl
>> ------------------------------------------
>> element = FiniteElement("Lagrange", "triangle", 2)
>> vector = VectorElement("Lagrange", "triangle", 2)
>>
>> v = TestFunction(element)
>> u = TrialFunction(element)
>> f = Function(element)
>> G = Function(vector)
>>
>> a = inner(grad(v), grad(u))*dx
>> L = v*f*dx
>> ------------------------------------------
>>
>> And I would like to do the following in C++:
>>
>> // in C++
>> a.G = Some_Function;
>>
>> Basically, I just want to attach to `a' some external function that does
>> NOT appear in the bilinear form. How hard would that be? I'm not sure
>> what the UFL syntax should be. This is for the higher order mesh stuff.
>
> I'm sure it's possible, but does it make sense that a has a function attached on
> which it does not depend?
> The code that will be generated from this form, will not use G in any way, so
> how do you plan on using it? For higher order mesh stuff, should one not just
> use:
> triangle = Cell("triangle", 2) # Cell() is defined in geometry.py in UFL
>
> and then define the finite element as:
>
> element = FiniteElement("CG", triangle, 1)
>
> maybe we should/could attach the function G to the cell if you intend to use
> this to compute the geometry?
>
> Kristian
Yes, that is exactly what I want to do! I'm not sure completely about the
Syntax though. Would this make sense:
--------------------------------------
# this is just a normal lagrange polynomial over a straight triangle
G = VectorElement("Lagrange", "triangle", 2)
# now define what the higher order element is
my_triangle = Cell("triangle", G)
# then define the element
element = FiniteElement("CG", my_triangle, 1)
--------------------------------------
That way it is clear that G influences what the shape of the triangle is,
and it splits up the implementation in a nice way. How about this?
- Shawn
_______________________________________________
FFC-dev mailing list
FFC-dev@xxxxxxxxxx
http://www.fenics.org/mailman/listinfo/ffc-dev