kicad-developers team mailing list archive

[José Ignacio <jose.cyborg@xxxxxxxxx>]

I don't believe that's correct !(!a || !b) is equal to a && b (de
morgan) http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/ietron/demorgan2.gif

On Tue, Apr 12, 2016 at 4:16 PM, Pereira, Patrick
<patrick.pereira@xxxxxxxxx> wrote:
> Hi,
>
> Corrections to avoid unnecessary boolean operations
> !(!a || !b) = a || b
>
> Best Regards,
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