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Re: Connection graph question
I can't look at the code this minute, but I think you basically have it
right. This call is quite expensive so if we can not trust the pin map to
be valid, we'll probably want to come up with some way to make a targeted
update so that we don't incur the computation time of a full recalculation.
On Wed, Dec 11, 2019 at 6:01 PM Wayne Stambaugh <stambaughw@xxxxxxxxx>
> I'm guessing this is primarily a question for Jon but maybe someone else
> can answer my question. My recent symbol inheritance merge revealed
> that the connection graph code has a serious fragility issue. This
> comment in the updateItemConnectivity function raised a red flag:
> // Assumption: we don't need to call UpdatePins() here because anything
> // that would change the pins of the component will have called it already
> It turns out this assumption was not only wrong, it was really wrong.
> Now that the LIB_PART of the SCH_COMPONENT is no longer a pointer link
> but an actual copy of the library symbol, any change to the underlying
> library symbol will result in stale pin map pointers. This is what has
> been causing all of the crash bugs. I cannot believe that we haven't
> had more issues. The only thing that saved us was as long as the
> original LIB_PART pointer was around somewhere, it wouldn't crash even
> if the connection information was completely wrong. I think I have
> fixed everyplace where the LIB_PART copy is changed in SCH_COMPONENT but
> that still leaves the issue of keeping the connection graph up to date.
> There are lots of places in the code where we call UpdateSymbolLinks().
> This will replace every single library symbol copy in the schematic with
> a new copy which will render the connect graph pointers completely out
> of date. What needs to be done to ensure the the connection graph is
> not stale? It appears to me that I have to call Recalulate( rootSheet,
> true ) is the correct thing to do but this will perform a complete
> rebuild of the connection graph. I'm guessing that has a lot of
> overhead involved in it. Is there a better way that I'm missing here?
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