mosquitto-users team mailing list archive

[Rene Kogels <renekogels@xxxxxxxxx>]

Thanks Nick. But still, loop() will not detect this. At least not with my
code, it will stay in the mosq_client.loop==0 loop when the connection to
the broker is lost. When I shut down the broker normally (service mosquitto
stop) the loop is stopped, and it tries to reconnect.

Code (part):

#Setup mosquitto client config
mosq_client = mosquitto.Mosquitto("client1")

#Connect mosquitto client; if we cannot connect, we will notice later with
mosq_client.loop!=0
mosq_client.connect("some host")

#Endless loop
while 1:

  while mosq_client.loop()==0:
      #Put some code here to read serial port to get some data

      #Publish it to the broker
      mosq_client.publish("serial/data", serial_data)

  #If we are here, we lost the connection with the mosquitto broker, so
sleep first and then try to reconnect.
  print("No connection with broker. Sleeping before retrying...")
  time.sleep(10)

  print("Trying to reconnect")
  mosq_client.connect("somehost")


Rene


On Fri, Dec 13, 2013 at 4:17 PM, Nicholas O'Leary  wrote:

> Hi Rene,
>
> if the broker goes away, the tcp layer will notify the client side that
> the connection has been lost and the usual connection-lost processing will
> occur within the client.
>
> Regards,
> Nick
>
>
> On 12 December 2013 20:09, Rene Kogels  wrote:
>
>> Hi all,
>>
>> I have a question about the behaviour of a python program that publishes
>> data, but to a broker that lost its network connection after a while. The
>> loop() function will probably not detect this as it will only detect
>> changes on the network socket caused by the broker. In this case the broker
>> could not tell the publisher it lost the connection.
>>
>> Will the publisher keep sending data, assuming there is a broker? Or will
>> it detect somehow the broker is gone (TCP does not get an ack)? Will the
>> publish function block?
>>
>> Thanks,
>> Rene
>>
>>
>>
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>