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[Bug 1676955] Re: disconnect() calls a sysDisconnectEvent of it's own

 

Migrating issues to Github, please follow the new discussion here:
https://github.com/Mudlet/Mudlet/issues/778

This issue needs to be closed and there is no appropriate status, so
will set it to "Opinion" just for migration purposes.

** Changed in: mudlet
       Status: New => Opinion

** Bug watch added: github.com/Mudlet/Mudlet/issues #778
   https://github.com/Mudlet/Mudlet/issues/778

** Bug watch added: github.com/Mudlet/Mudlet/issues #821
   https://github.com/Mudlet/Mudlet/issues/821

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https://bugs.launchpad.net/bugs/1676955

Title:
  disconnect() calls a sysDisconnectEvent of it's own

Status in Mudlet:
  Opinion

Bug description:
  Sample Code:

  function doubleEcho()
    cecho("\n<black:yellow>This will echo twice, but only if currently connected to the MUD when disconenct() is called")
  end

  registerAnonymousEventHandler("sysDisconnectionEvent","doubleEcho")

  disconnect()

  
  Explanation:

  sysDisconnectEvent is designed to let you know that the connection to
  the MUD has been terminated. However, regardless of whether there is a
  connection to the MUD, calling the disconnect() function raises
  sysDisconnectEvent. When connected to a MUD, this results in
  sysDisconnectEvent being called twice if you manually run a
  disconnect(). If the MUD disconnects you on the other hand, you only
  get one sysDisconnectEvent, as proper.

  Usually this is no problem. However, sometimes a function that is
  registered to sysDisconnectEvent will have issues if it is run twice.
  Other times you may not want said function to run unless already
  connected to the MUD when disconnect() is called.

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References