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[RaiMan <question157012@xxxxxxxxxxxxxxxxxxxxx>]

Question #157012 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/157012

    Status: Open => Answered

RaiMan proposed the following answer:
It is a normal situation for every kind of programming since Turing invented his machine:
The more different cases should be handled in one program, the more decisions you will have to make and its increase mostly is more exponential than linear.
And the decision tool in Sikuli/Python is if/elif/else.

So be happy, that there is if/elif/else, to help you with your workflow
and use it.

So the right question is: How to make decisions in a readable, elegant,
efficient and robust way.

--- Taking your example:
Can both imagever's be there the same time? Since I guess no:

if exists(imgver1):
    click(imgver1)
elif exists(imgver2):
    click(imgver2)
else:
    print "None of them"
    exit(1)

this only tests until the first match is found (a case/switch in other
languages).

--- One more thing
for efficiency use:

if exists(imgver1):
    click(getLastMatch())

you save one search.

--- One last thing:
When I am right with my guessing, in the moment you do your case study, one imagever must be there. 
Then it is even more efficient to use:

if exists(imgver1, 0):
    click(imgver1)
elif exists(imgver2, 0):
    click(imgver2)
else:
    print "None of them"
    exit(1)

In the case without the second parameter as 0, a not successful search would last 3 seconds (standard waiting time). with the 0 it comes back in the average with 0.5 seconds or less.
So with 4 cases and the 4th case matches, it would take 10 seconds against maximum 2 seconds with the 0.
The magic is, that exists(img,0) only makes one search and comes back with the result.

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