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[RaiMan <question172656@xxxxxxxxxxxxxxxxxxxxx>]

Question #172656 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/172656

RaiMan posted a new comment:
@ vitalliuss

The above solution is only usable if you accept the leap years problem, when dividing by 365.
The time delta counts days, which do not have a leap year problem.

BTW: timedelta.days/365 gives 22 and not 22.6 (integer division)

So for this purpose the leap years do no harm.

But if you really want to minimize the "error":
correctLeap = 365*4+1
theDays = timedelta.days
years = (theDays - theDays/correctLeap)/365

this corrects the days value by subtracting the contained leap days
before dividing by 365 (error +/-1)

But this does not take into account, that years ending with 00 are
normal years ;-)

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