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[RaiMan <question174139@xxxxxxxxxxxxxxxxxxxxx>]

Question #174139 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/174139

RaiMan proposed the following answer:
this works in Win7

import os
dir = r"c:\folder\subfolder" # the directory containing the text file
fname = "logging.txt" # the filename of the text file
os.popen("start /D %s %s"%(dir, fname)) # using the start command
# which opens the program that is associated with the extension (.txt in this case)

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