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[RaiMan <question179084@xxxxxxxxxxxxxxxxxxxxx>]

Question #179084 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/179084

    Status: Open => Answered

RaiMan proposed the following answer:
--1. exact() seems to have a bug - use similar(0.99) instead. But even
that normally is not needed. But give it a try.

--2. for these situations, the first version is principally the choice,
since in the second case, a not successful find() would stop the script
with a FindFailed exception.

--3. If you make a case decision with exists(), you should use
exists(image,0), so it does not wait 3 seconds, if the case is not true
(image not there).

So this should work as expected:

def chkpic():
    if exists("img1", 0):
       return 1
    elif exists("img2", 0):
       return 2
    elif exists("img3", 0):
       return 3

To be more flexible and have a chance, to debug the situation:


def chkpic(debug = False):
    ret = 0
    if exists("img1", 0):
       ret = 1
    elif exists("img2", 0):
       ret = 2
    elif exists("img3", 0):
       ret = 3
    if debug and ret > 0:
        print ret, "---", getLastMatch()   

So when using chkpic(), no message will be printed, but for debugging
purposes you can use chkpic(True), which would print you a message,
showing the match, which gives you a chance to check e.g. the similarity
score.

To make this function even more generally usable:

def chkpic(images, debug = False):
    ret = 0
    for i in range(len(images)):
        if exists(images[i], 0):
            ret = i
            break
    if debug and ret > 0:
        print ret, "---", getLastMatch()   

and the usage would be:

chkpic(("img1", "img2", "img3"))

or

chkpic(("img1", "img2", "img3"), True)

So you can use the function in different places with different lists of
images.

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