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[Shawn Robertson <question222218@xxxxxxxxxxxxxxxxxxxxx>]

New question #222218 on Sikuli:
https://answers.launchpad.net/sikuli/+question/222218

All I want to do in this script is just open a windows explorer window to a specific directory so that I can then use the IDE to interact with specific files to right click etc..

before I do that I just want to open "C:\tssmoketest\2014\"

there are several files in here I need to right click on to go to properties etc and i can handle that portion fine.

in my script I have:

import os
import subprocess

tsVersion = input("Enter your version ie.. 2013, 2014 etc:", "2014")

subprocess.Popen('explorer os.path.join('c:', os.sep, 'tssmoketest', tsVersion)')

this doesnt work as my formatting is incorrect.

So i try to get basic with it and just use:

subprocess.Popen('explorer "C:\tssmoketest\2014"')

and this works however it just keeps opening my local user profile documents folder and I dont know why this is.

I then try to use:

os.system('start "C:\tssmoketest\2014"')


and all this does is open a command line terminal with the file path c:\program files (x86)\Sikuli X>



I'm still learning python and reading here and there to learn on the fly so my apologies for the poor coding. Defintely putting notes in my scripts to help retain and learn along the way. 


I didn't think just opening a specific windows directory in windows explorer woudl be so hard.

I can do it another way which is:

type('r', KeyModifier.WIN)
wait("Typethenameo.png")
paste(os.path.join('c:', os.sep, 'tssmoketest', tsVersion, 'data01'))
type(Key.ENTER)


but its longer and its ugly and figured I could use somethign similar to someapp.open() 



Any help is much appreciated.

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