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Message #19604
Re: [Question #121539]: Windows: openApp parameter support --- use start menu instead or WIN-R
Question #121539 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/121539
Assignee: None => RaiMan
Description changed to:
--- solution
- to be fixed in version 1.1
use shellexecute in WinUtil (see comment #12)
--------------------------------------------------------------------
I was hoping to open a URL directly in the openApp statement by passing
the URL as a parameter to the iexplore.exe command, such as:
openApp('C:\Program Files\Internet Explorer\iexplore.exe
"http://www.google.com"')
This almost works, but the URL appears in Explorer as:
http://www.google.com%22%22/
The presence of the two escaped double quotes mean that the URL doesn't
resolve. I've tried various combinations of escaping the double quotes,
and also trying to strip them from a variable, but without success. Am I
doing sometthing wrong, or is openApp not designed to pass parameters?
Or is this just a simple bug?
Thanks and keep up the good work - Sikuli is a really interesting
application.
(Problem occurs on Windows XP SP3 in Sikuli 0.10.2)
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