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[RaiMan <question272088@xxxxxxxxxxxxxxxxxxxxx>]

Question #272088 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/272088

    Status: Open => Answered

RaiMan proposed the following answer:
Yes, one event for one image (currently ;-)

This is the appropriate solution for version 1.1.0+:

r = Region(Region(2516,495,694,273))
leftSide = [("left1.png"), ("left2.png"), ("left3.png"), ("left4.png"), ("left5.png"), ("left6.png"), ("left7.png"), ("left8.png"), ("left9.png"), ("left10.png"), ("left11.png")]
rightSide = [("right1.png"), ("right2.png"), ("right3.png"), ("right4.png"), ("right5.png"), ("right6.png"), ("right7.png"), ("right8.png"), ("right9.png"), ("right10.png"), ("right11.png"), ("right12.png")]
neitherSide = [("center1.png"), ("center2.png"), ("center3.png"), ("center4.png")]

def moveLeft(event):
    type(Key.LEFT)
    event.repeat(0.2) # continue observation after 0.2 seconds

def moveRight(event):
    type(Key.RIGHT)
    event.repeat(0.2) # continue observation after 0.2 seconds

# register the events with region r
# one event == one image
for ls in leftSide:
  r.onAppear(ls, moveRight)
for rs in rightSide:
  r.onAppear(rs, moveLeft)
nor rs in neitherSide:
  r.onAppear(ns, moveRight)

# run the observation
r.observe(FOREVER)

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