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[Erwin <question295370@xxxxxxxxxxxxxxxxxxxxx>]

New question #295370 on Sikuli:
https://answers.launchpad.net/sikuli/+question/295370

I want to edit several text files in a directory and want to open them in Notepad (windows) type some text and close them.

First I get the files in the directory to process them one by one
import os
dir = "C:/Users/win7/Desktop/textfiles"
for e in os.listdir(dir):
    fileName = os.path.join(dir, e)
    print fileName
print "all files processed"

this outputs the following:
C:/Users/win7/Desktop/textfiles\1.txt
C:/Users/win7/Desktop/textfiles\2.txt
C:/Users/win7/Desktop/textfiles\3.txt
C:/Users/win7/Desktop/textfiles\4.txt
C:/Users/win7/Desktop/textfiles\5.txt
all files processed

So the variable fileName contains the complete path to the file I want to edit. How do I use the App.open command to open notepad with that file?

I tried:
   App.open ("notepad" fileName)

but that gives:
[error] script [ Naamloos ] stopped with error in line 6 at column 24
[error] SyntaxError ( "no viable alternative at input 'fileName'", )

Then I tried
App.open ("notepad fileName")

now notepad starts but complains it can not find the file fileName.txt

I tried several variations with ' and " and commas but none works. Is this possible and if so how should it be done?



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