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[RaiMan <sikulix@xxxxxxxxxxx>]

** Summary changed:

- [1.1.2] App.open() is not returning the instance --- workaround
+ [1.1.2] App.open() is not returning the instance --- docs have to be adjusted

** Changed in: sikuli
       Status: In Progress => Fix Committed

** Description changed:

- ------------------ workaround
- use
- App app = new App("C:\\Program Files (x86)\\Microsoft Office\\root\\Office16\\EXCEL.EXE").open();
+ ------------------ usage information
+ In case the given program name or path to program contains blanks, the complete string has to be enclosed in extra apostrophes:
+  
+ App app = App().open("\"C:\\Program Files (x86)\\Microsoft Office\\root\\Office16\\EXCEL.EXE\"");
+ 
+ An appropriate hint has to be added to the docs.
  
  -----------------------------------------------
  
  App.open() method call does not return the instance of the opened
  application instead it always return null whether application open
  successfully or not.
  
  method is "private App openAndWait(int waitTime)". Because of "notFound"
  variable is false it returns null. But "appPID" is greater than 0.
  
  sikulixapi - 1.1.1 version
  OS - 64 bit windows 10
  
  How to reproduce.
  
  App app = App.open("C:\\Program Files (x86)\\Microsoft
  Office\\root\\Office16\\EXCEL.EXE");
  
  this will return null but excel will be opened successfully.
  
  Method location in App.java class
  
  private App openAndWait(int waitTime) {
      if (isImmediate) {
        appPID = _osUtil.open(appNameGiven);
      } else {
        AppEntry appEntry = makeAppEntry();
        init(_osUtil.open(appEntry));
      }
      if (appPID < 0) {
        Debug.error("App.open failed: " + appNameGiven + " not found");
        notFound = true;
      } else {
        Debug.action("App.open " + this.toStringShort());
      }
      if (isImmediate && notFound) {
        return null;
      }
      if (waitTime > 0) {
        if (!isRunning(waitTime)) {
          return null;
        }
      }
      return this;
    }
  
  Always execute this line.
  if (isImmediate && notFound) {
        return null;
  }

-- 
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https://bugs.launchpad.net/bugs/1762381

Title:
  [1.1.2] App.open() is not returning the instance --- docs have to be
  adjusted

Status in Sikuli:
  Fix Committed

Bug description:
  ------------------ usage information
  In case the given program name or path to program contains blanks, the complete string has to be enclosed in extra apostrophes:
   
  App app = App().open("\"C:\\Program Files (x86)\\Microsoft Office\\root\\Office16\\EXCEL.EXE\"");

  An appropriate hint has to be added to the docs.

  -----------------------------------------------

  App.open() method call does not return the instance of the opened
  application instead it always return null whether application open
  successfully or not.

  method is "private App openAndWait(int waitTime)". Because of
  "notFound" variable is false it returns null. But "appPID" is greater
  than 0.

  sikulixapi - 1.1.1 version
  OS - 64 bit windows 10

  How to reproduce.

  App app = App.open("C:\\Program Files (x86)\\Microsoft
  Office\\root\\Office16\\EXCEL.EXE");

  this will return null but excel will be opened successfully.

  Method location in App.java class

  private App openAndWait(int waitTime) {
      if (isImmediate) {
        appPID = _osUtil.open(appNameGiven);
      } else {
        AppEntry appEntry = makeAppEntry();
        init(_osUtil.open(appEntry));
      }
      if (appPID < 0) {
        Debug.error("App.open failed: " + appNameGiven + " not found");
        notFound = true;
      } else {
        Debug.action("App.open " + this.toStringShort());
      }
      if (isImmediate && notFound) {
        return null;
      }
      if (waitTime > 0) {
        if (!isRunning(waitTime)) {
          return null;
        }
      }
      return this;
    }

  Always execute this line.
  if (isImmediate && notFound) {
        return null;
  }

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