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Message #49095
[Question #675666]: [1.1.4]How to get all apps with the same name on windows
New question #675666 on Sikuli:
https://answers.launchpad.net/sikuli/+question/675666
system: windows 10
situation: There are 5 applications with the same name running on the system. (With different PIDs)
problem:
In version 1.1.2, I can use App("some-text-of-window-title") to get all the windows of the 5 app. But in version 1.1.4, it failed.
If I use APP("app-name-show-in-taskmanager"), it only returns the first app-object.
So , I want to know how can I get All the windows that contains the same keyword in their window titles. My scripts are as follow(It runs well in 1.1.2, but failed to find any windows in 1.1.4):
def getApp(sKeyWord):
allClient = App("+%s" % sKeyWord)
clientList = []
windowList = []
if not allClient:
error_message("No client found with title %s" % sKeyWord)
return clientList, 0, windowList
iMainWindowIndex = getMainWindowIndex(sKeyWord)
for i in range(10):
oneClient = allClient.focus(i)
#oneClient = allClient
pid = oneClient.getPID()
if pid <= 0:
break
info_message("========Client:%d pid=%s=============" % (i, pid))
w = oneClient.window(iMainWindowIndex)
if not w.isValid():
continue
clientList.append(oneClient)
windowList.append(w)
info_message("title = %s, client found:%d" % (sKeyWord, len(clientList)))
return clientList, len(windowList), windowList
getApp("Revision")
result:
in 1.1.2:
[22:37:33][4299:4885] ========Client:0 pid=2932=============
[22:37:33][4299:4885] ========Client:1 pid=1992=============
[22:37:33][4316:4885] title = Revision, client found:2
in 1.1.4:
[error] App.focus failed: not running: [-1:+Revision (???)] +Revision
[22:38:45][4316:4885] title = Revision, client found:0
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