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[Bug 1885858] Re: VNCstart does not return on failure

 

RaiMan,

Thank you for looking into this.

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https://bugs.launchpad.net/bugs/1885858

Title:
  VNCstart does not return on failure

Status in Sikuli:
  In Progress

Bug description:
  Python version 3.7.4 64 bit
  Sikuli 2.0.4 
  Windows server 2016 DC 64 bit & windows 10 64bit

  Procedure:
  1. installed python version 3.7.4 with sikuli 2.0.4 (windows server 2016 DC 64 bit & windows 10 64bit)
  2. using Git clone cloned the source to local machine
  3. created the reboot script in python 
  4. Accessing device using VNC viewer 6.19.107 using sikuli and python
  5. performing reboot operation in loop 
  6. used below code to connect the VNC 
  def connect(unit):
      if unit['connection'] == 'vnc':
          vnc = vncStart(ip=unit['ip'], port=5900, password=unit['passwd'], connectionTimeout=10, timeout=120000)
          if not vnc:
            print "Unable to connect to %s using password %s over VNC" % (unit['ip'], unit['passwd'])
            exit()
          return vnc
      elif unit['connection'] == 'vlc':
          apps.append(openApp('cvlc -f v4l2:///dev/video2'))
          return Screen(0)
      elif unit['connection'] == 'pi':
          pass
      return SCREEN

  issue faced:
  Running the script using command prompt. Able to connect the VNC and reboot the device upto 39th iteration without any issue, in 40th iteration its trying to connect the VNC but not connecting, there is no error messages, its strucking to connect the VNC. Verified this multiple times. Also verified this in sikuli 2.0.2 facing the same issue.

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References