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Re: [Question #694893]: Open an App linux

 

Question #694893 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/694893

Description changed to:
Hi all,

I am trying to open a custom software application on linux via Sikuli. 
But traditional way App.open("some app") and also with the path to the app. 
Its giving the following error:

[error] findWindow:
[error] error in command [wmctrl, -lpGx]
[errout] X Error of failed request:  BadWindow (invalid Window parameter)
  Major opcode of failed request:  20 (X_GetProperty)
  Resource id in failed request:  0x2e00169
  Serial number of failed request:  15
  Current serial number in output stream:  15


But when I open the app manually Sikuli performs as expected. 

OS : Fedora 33
Sikuli: 2.0.4


Thanks in advance.

Regards,
Varun Umesh

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