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Message #56408
Re: [Question #694893]: Open an App linux
Question #694893 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/694893
Status: Needs information => Open
Varun Umesh gave more information on the question:
myApp = App.("/home/tm/Documents/mvts/MCVTS/bin/MCVTS")
myApp.open()
myApp.focus()
I have tried with both .exe and .app extentions.
App type : executable (application/x-executable)
I have also tried with these syntax:
myApp = App("/myapps/someApp.app")
myApp = App(r"c:\myapps\someApp.exe")
myApp = App(r'"c:\folder with spaces\someApp.exe"')
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