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Message #54757
Re: Dagens tricky shell spørgsmål.
On Wed, 11 Sep 2002, Mads Bondo Dydensborg wrote:
> > Det hedder coprocesser. ksh og zsh kan det. Jeg har aldrig proevet.
> > Klip fra zsh manpage:
> >
> > If a pipeline is preceded by `coproc', it is executed as a
> > coprocess; a two-way pipe is established between it and
> > the parent shell. The shell can read from or write to the
> > coprocess by means of the `>&p' and `<&p' redirection
> > operators or with `print -p' and `read -p'. A pipeline
> > cannot be preceded by both `coproc' and `!'. If job con
> > trol is active, the coprocess can be treated in other than
> > input and output as an ordinary background job.
> >
> > Men jeg kan ikke lige faa det til at virke...
>
> Hmm. Jeg er ikke sikker på at jeg kan læse det som at det løser mit
> problem.
>
> jeg vil have opførsel som:
>
> ./mit_program > fifo < fifo
>
> Er det det coproc giver mig?
Som jeg læser det, nej. coproc sætter en pipeline i baggrunden og laver to
specielle fd'er som er pipelines input og output. Altså:
coproc a | b && cat >&p > <&p
hmmm.
Hvis man kan
coproc a | b < >&p
ville det jo virke.
Kan man det?
Mads
--
Mads Bondo Dydensborg. madsdyd@xxxxxxxxxxxx
Value your freedom, or you will lose it, teaches history. "Don't bother us
with politics," respond those who don't want to learn.
- Free software proponent, Richard M. Stallman
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