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[Bug 1411318] Re: arbitrary code execution

 

Have you reported this issue to the upstream bash developers?


** Changed in: bash (Ubuntu)
       Status: New => Confirmed

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https://bugs.launchpad.net/bugs/1411318

Title:
  arbitrary code execution

Status in bash package in Ubuntu:
  Confirmed

Bug description:
  "The problem with bash's name references

  Bash 4.3 introduced declare -n ("name references") to mimic Korn
  shell's nameref feature, which permits variables to hold references to
  other variables (see FAQ 006 to see these in action). Unfortunately,
  the implementation used in Bash has some issues.

  {…} Bash's name reference implementation still allows arbitrary code
  execution:

  $ foo() { declare -n var=$1; echo "$var"; }
  $ foo 'x[i=$(date)]'
  bash: i=Thu Mar 27 16:34:09 EDT 2014: syntax error in expression (error token is "Mar 27 16:34:09 EDT 2014")

  It's not an elegant example, but you can clearly see that the date
  command was actually executed. This is not at all what one wants."

  source: http://mywiki.wooledge.org/BashFAQ/048

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References