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Re: singular function and Quadrature element

 

On Sun, Apr 19, 2009 at 11:47:42PM +0200, Martin Sandve Alnæs wrote:
> In principle, but:
> 
> Quadrature elements currently don't work in SFC,
> don't know what FFC can do at this point.
> 
> UFL does not (yet) standardize how to specify quadrature
> rules manually if you need a particular rule. But I don't think
> the Gauss rules used by SFC have points on the boundary.
> 
> Martin

FFC uses the quadrature points given by FIAT and none of them are on
the boundary as far as I can tell.

So this should work, but note that you can't differentiate functions
defined on a quadrature element.

-- 
Anders

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