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Re: Definition of grad

 

On Fri, Nov 06, 2009 at 06:45:48PM +0100, Harish Narayanan wrote:
> Anders Logg wrote:
> > This is something we've discussed before, but I want to discuss it
> > again.
> >
> > Could we change the definition of the gradient of a vector to be the
> > "normal" definition:
> >
> >   grad(u) = du_i / dx_j
> >
> > ?
>
> And while this is up for discussion, I would also like the divergence to
> be defined as it usually is:
>
> div(A_{ij..m}) = A_{ij..m,m}

What does Martin think?

--
Anders

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