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Message #02066
Re: diagonal of a tensor
On Thursday November 3 2011 13:54:25 Martin Sandve Alnæs wrote:
> So I couldn't resist and implemented it :)
Nice!
I knew you would not resist that one ;)
Johan
> To be on the safe side because of the beta I only added
> functions diag and diag_vector which use other ufl operators,
> so this does not introduce any new types to UFL and does
> not pose any risk for existing code.
>
> See docstrings and tests for usage.
>
> Martin
>
> On 3 November 2011 07:38, Martin Sandve Alnæs <martinal@xxxxxxxxx> wrote:
> > There is no such operator, but it would make sense yes.
> >
> > Just define it yourself for now with def diag(A), should be trivial to
> > add to ufl.
> >
> > Martin
> >
> > Den 3. nov. 2011 00.13 skrev "Johan Hake" <johan.hake@xxxxxxxxx> følgende:
> >> Hello!
> >>
> >> Is there an easy way to extract the diagonal of a square tensor in ufl?
> >> I know
> >> I can do:
> >>
> >> diag = as_vector([A[0][0], A[1][1]])
> >>
> >> but it would make sense to have something like:
> >>
> >> diag(A), A.diag()
> >>
> >> Johan
> >>
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