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Re: Parallelepiped instead of cube

 

> This is a pack.py
> ..
> ..
> ..
> 
> ii,jj,kk=[range(0,int(2*dim[0]/a)+1),range(0,int(dim[1]/h)+1),range(0,int(dim[2]/h)+1)]
>     for i,j,k in itertools.product(ii,jj,kk):
Oh, my fault, it is a leftover from pervious code where dim was etxtents
of the box, not whole dimension. Thanks for spotting that, I will fix
it. Thanks for the ellipsoid also.

V.





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