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["Sergei D." <dorofeenko@xxxxxxxxx>]

> > But you speak about elastoplastic law with different stiffness for 
> > loading/unloading.
> > I speak about viscoelastic law (with constant stiffness):
> > F = k x + c dx/dt
> > So, if dx/dt>0 (loading) then F > F_elastic=k x,
> > and if dx/dt<0 (unloading) then F<F_elastic
> > ok?
>
> Ok for these inequalities ! Thanks for explanations.
> And so you suggest to use this comparison of force values to deduce 
> something about time steps ?
No! For given 'k' and 'c' we has a time, when x runs from 0 to max and 
again to 0, i.e. it is a half-period of oscillation or a collision time. 
So, time step is a fraction of this half-period.

--
Best regards,
Sergei D.