yade-users team mailing list archive

[Jan Stránský <honzik.stransky@xxxxxxxxx>]

Hi Veljko,

you can call predicate for testing. It will test if Vector3 is inside
predicate or not. You can optionally use second parameter to specify "pad"
= sphere radius.

pred = pack.inAlignedBox((0,0,0),(10,10,10))
s = sphere((0,0,0),1)
for pos in ((.9,.9,.9),(1.1,1.1,1.1)): # whatever else..
s.state.pos = pos
print pred(s.state.pos,s.shape.radius)

cheers
Jan




2015-02-12 15:01 GMT+01:00 velimier <question262000@xxxxxxxxxxxxxxxxxxxxx>:

> New question #262000 on Yade:
> https://answers.launchpad.net/yade/+question/262000
>
> Hi,
> is there method to determine whether sphere lies within given predicate?
>
> Thanks,
> Veljko
>
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