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Message #12930
Re: [Question #295301]: calculate external work in Uniaxial Strainer
Question #295301 on Yade changed:
https://answers.launchpad.net/yade/+question/295301
Yor1 posted a new comment:
I change the manner that i calculate the displacement
if(asymmetry==0){
dAX*=.5;
for(size_t i=0; i<max(posIds.size(),negIds.size()); i++){
displacement+=2*dAX;
}
}
I'm inspiring from the calculation of the displacement for "asymmetry!=1" and "assymetry!=-1".
For example, the displacement in the case of "asymmetry!=1" is calculated like this:
if(asymmetry!=1){
for(size_t i=0; i<negIds.size(); i++){
negCoords[i]-=dAX;
axisVel(negIds[i]) = -dAX/scene->dt; // update current position
}
}
Jabrane.
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