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[Bug 664416] [NEW] Problem insert 2nd contact of a Partner

 

Public bug reported:

hi, 
this is my problems (bugs?):
On a new installation of 5.0.14 on ubuntu 10.4, I create a new DB with minimal profile and only install base_contact module.
In this environment I create a new partner, insert data and function "Invoice", when I insert a contact in the bottom part of the form, opening with F2 the contact list, and click NEW, there is no problems; i decide, after SAVE the record (also partner), to add a second contact, clicking F2 I get, instead of opening Contact list, the only contact previously insert. 
Now to get my contact list I have to write a non sense name ex: "abdc" press F2, so the program think that I want search this name and so I can create a new record.
The problem is only in this case because when I have 2 contact the F2 open the search contact form (because there are more than one contacts...)
i know that in some other case it is the correct behaviour, but still in this example?

Hope it's clear...

** Affects: openobject-addons
     Importance: Undecided
         Status: New

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Problem insert 2nd contact of a Partner
https://bugs.launchpad.net/bugs/664416
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Status in OpenObject Addons Modules: New

Bug description:
hi, 
this is my problems (bugs?):
On a new installation of 5.0.14 on ubuntu 10.4, I create a new DB with minimal profile and only install base_contact module.
In this environment I create a new partner, insert data and function "Invoice", when I insert a contact in the bottom part of the form, opening with F2 the contact list, and click NEW, there is no problems; i decide, after SAVE the record (also partner), to add a second contact, clicking F2 I get, instead of opening Contact list, the only contact previously insert. 
Now to get my contact list I have to write a non sense name ex: "abdc" press F2, so the program think that I want search this name and so I can create a new record.
The problem is only in this case because when I have 2 contact the F2 open the search contact form (because there are more than one contacts...)
i know that in some other case it is the correct behaviour, but still in this example?

Hope it's clear...





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