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Anders Logg wrote:
No, it has not been implemented yet but it's something we desperately need. If we define the L2 projection Pu of u onto V by (Pu, v) = (u, v) for all v in V then the problem is in evaluating the integral on the right-hand side: (u, v) where now u and v are defined on different meshes. My suggestion would be to evaluate this by quadrature at run-time, using the generated UFC function evaluate_basis and IntersectionDetector/GTS which is very fast at finding the overlap between cells.
Hmm, ok. I will try to compute the integral on the right-hands at runtime using quadrature and use it to determine Pu.
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