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Message #01746
Re: [Question #121539]: openApp parameter support
Question #121539 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/121539
NMANOS posted a new comment:
Thanks RayMan,
Eventually that's the Function I use:
def launchWinApp(command, windowTitle=''):
type("r", KEY_WIN)
wait(1)
App.focus('Run')
paste(command.encode('string-escape'))
type(Key.ENTER)
wait(5)
if exists(windowTitle):
winApp = App(windowTitle)
else:
winApp = App.focusedWindow()
windowTitle = winApp.text().splitlines()[0]
print 'Returning Application with Title: %s' % windowTitle
return winApp
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