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[RaiMan <question170179@xxxxxxxxxxxxxxxxxxxxx>]

Question #170179 on Sikuli changed:
https://answers.launchpad.net/sikuli/+question/170179

    Status: Open => Answered

RaiMan proposed the following answer:
if you do it this way, either n must be a string or m must be a number.

1. both as string:

n= "73"
if m==n:
       print "exact match"
else:
       print "found something else"

2. both as number:

m =int(r.text())
n= 73
if m==n:
       print "exact match"
else:
       print "found something else"

comment on 1:
this might still fail, since m might contain characters that are not visible when printed.
so you might use:
if m.count(n) > 0:

this looks for the string n in m.

comment on 2:
this might fail, if m cannot be converted to an integer, because the string not only contains digits.
You might use a regex, to get the number

import re
m = r.text()
re.match(".*(\d*?)", m)
mn = int(re.group(1)) if re.group(1) else Null
if mn and mn == n:

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