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[Bug 1224481] Re: [1.0.1 ok] ScriptJython: exitcode not returned to commandline when using exit(n)

 

I have upgraded to the latest version (2013.9.13), but still could not
get the right exit code

[exec]   File "C:\Users\user\Desktop\scripts_folder\deployment.sikuli\deployment.py", line 112, in <module>
     [exec]     exit(3)
     [exec]   File "C:\sikuli\sikuli1.0.1\sikuli_download\sikuli-ide.jar\Lib\sikuli\Sikuli.py", line 232, in exit
     [exec]     sys.exit(code)
     [exec] SystemExit: 3
     [exec] [info] Exit code: 1

I don't know why the sikuli throw the exception when I try to call the
exit(3)  method ?

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https://bugs.launchpad.net/bugs/1224481

Title:
  [1.0.1 ok] ScriptJython: exitcode not returned to commandline when
  using exit(n)

Status in Sikuli:
  Fix Committed

Bug description:
  ----- fixed with version 1.0.1 per September 12 at 5 pm gmt+1
  repeat setup after this time to get the fixed version
  tested on Mac, but should work on Win/Linux too
  ----------------------------------------------------------
  I try to stop the sikuli process with error exit code by call the api sys.exit(2).

  But it throws an exception

       [exec] Traceback (most recent call last):
       [exec]   File "C:\Users\user\Desktop\scripts_folder\deployment.sikuli\deployment.py", line 100, in <module>
       [exec]     sys.exit(2)
       [exec] Sy

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