sikuli-driver team mailing list archive

[markshao <mark.shao@xxxxxxx>]

Append an example

Suppose there is an application name test.exe under the directory A.
Whenever the application is started , it start an daemon web service at
the same time to provide service for download the html files in the
folder HTML under A.

if I directly go the A directory , start the test.exe. The service is ok
, I can see the file list in the browser with the host:port

But I use the sikuli code App.open('c:\A\test.exe') , then the service
always return 404 not found error.

I guess the problem maybe the context path of the application process.
So I start the application from App.open() , the context path of the
application process maybe the path where sikuli is located. So the
application process could not find HTML folder .

So whether we should set the context path for the application process.

For example the App.open('c:\A\test.exe') should set the context path to
be 'C:\A'

Maybe I am wrong , need your advice . Thanks.

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https://bugs.launchpad.net/bugs/1218755

Title:
  [request] The context path should been set when start new application

Status in Sikuli:
  Incomplete

Bug description:
  The application which I need to start from sikuli may need to start a
  internal service from it self. The service need to read the relative
  path folders from it's own directory.

  I try to use the script

  App.open(xxx.exe)

  to start the application , but when I try to get the service , always
  got 404 error.

  Whether the sikuli should provide the parameters to specify the
  context path when start the new application via the App.open api

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