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Message #26369
[Question #250174]: __file__ or equivalent?
New question #250174 on Sikuli:
https://answers.launchpad.net/sikuli/+question/250174
I would like to locate a file relative to the executing sikuli script.
In normal Python I would do this based on the __file__ predefined value, but it does not seem to be defined.
Is there some other way to get "path to this script" or do I have to hard-code the path?
Thanks,
DC
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