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underlige entries i kern.log på fw.

 


Hej allesammen,

er der nogen der har den fornødne expertise til at kunne decifrere nedenstående
for mig ?

jan 24 11:59:46 firewall kernel: Packet log: input - eth2 PROTO=6 1000 T=128
(#5)
Jan 24 12:00:15 firewall kernel: Packet log: input - eth2 PROTO=17
10.30.250.51:138 10.30.250.255:138 L=237 S=0x00 I=13964 F=0x0000 T=128 (#5)
Jan 24 12:01:45 firewall kernel: Packet log: input - 0 T=128 (#5)
Jan 24 12:01:47 firewall kernel: Packet log: in (#5)
Jan 24 12:01:53 firewall kernel: Packet log: input - eth2 PROTO=47 S=0x00
I=44694 F=0x4000 T=128 (#5)
Jan 24 12:01:57 firewall kernel: Packet log: input - eth2 PROTO=6 10x4000 T=128
(#5)
Jan 24 12:01:59 firewall kernel: Packet (#5)
Jan 24 12:02:07 firewall kernel: Packet log: input - eth2 PROTO=6 10.30.25 (#5)
Jan 24 12:02:11 firewall kernel: Packet log: input - eth2 PROTO=6
10.30.250.5=128 (#5)
Jan 24 12:02:15 firewall kernel: Packet log: input - eth2 P128 (#5)
Jan 24 12:02:22 firewall kernel: Packet lo (#5)
Jan 24 12:02:26 firewall kernel: Packet log: input - eth2 P5)
Jan 24 12:02:35 firewall kernel: Packet log: input - eth2 PROTS=0x00 I=33692
F=0x4000 T=128 (#5)
Jan 24 12:02:43 firewall kernel: Packet log: input - eth2 PROTO=6
10.30.250.51:5631 10.31.77 F=0x4000 T=128 (#5)
Jan 24 12:02:50 firewall kernel: Packet log: input - eth2 PROTO=T=128 (#5)
Jan 24 12:02:59 firewall kernel: Packet log: input - eth2 PROTO=6 10. T=128 (#5)
Jan 24 12:03:01 firewall kernel: Packe416 F=0x4000 T=128 (#5)
Jan 24 12:03:07 firewall kernel: Packet log: input - eth2 PROTO=6
10.30.250.51:5631 10.31.250.1945 F=0x4000 T=128 (#5)
Jan 24 12:03:08 firewall kernel: P T=128 (#5

Mvh

Klavs Klavsen
Berlingske Online