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Message #40384
Re: $variable for output i bash
On Wed, Aug 01, 2001 at 10:13:59PM +0200, Per Jørgensen wrote:
> jeg har fundet ud af følgende endtil vidre
>
> FILE=`cat /home/pej/router_ip`
> for ROUTER in $FILE; do
> snmpget $router $community interfaces.ifTable.ifEntry.ifAdminStatus.1 & 1
> if ????
FILE=`cat /home/pej/router_ip`
for router in $FILE; do
if snmpget $router $community interfaces.ifTable.ifEntry.ifAdminStatus.1
echo $router er oppe.
else
echo $router er nede.
fi
done
(Ikke testet).
--
Best Regards
Emil S. Hansen - esh@xxxxxxxxxxxxx - ESH2-DK
UNIX Administrator, Berlingske Tidende - www.berlingske.dk
"I started developing this under a VLIW architecture, but began to find
the length of the instruction words prohibitive - I'd keep getting
distracted mid-word, and my coding efficiency suffered accordingly." -
AC on /.
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