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Re: friction dissipation

 

On 18 May 2010 16:57, Bruno Chareyre <bruno.chareyre@xxxxxxxxxxx> wrote:

>
>
>>  No. It is the increment of displacement.
>
> Example :
> 1) time t : us_total=1, us_elastic=0.1, us_plastic=0.9, fs=0.1*ks
> 2) assume an increment dus between t and t+dt
> 3) trialFs = previousFs + dus*ks = us_elastic*ks + dus*ks =
> ks*(us_elastic+dus)
> 4) 1/ks*(trialFs-previousFs) = ? .... dus
>

Ok, I was clearly seeing trialFs in the wrong way, sorry. So now to me it is
corrected the way you proposed for the friction dissipation (not the current
one but the revised one I reported in the previous mail). If you agree could
you commit it, please? Thanks.
Chiara

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