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Re: How to keep a constant stress boundary?

 

Thanks, Bruno,

I checked the code, but I still did not understand the physical meaning of
the code.
May I ask : what is the physical meaning behind the code? or what is the
mathematic of the algorithm?
how is it called ?

Thanks a lot.
yongfeng



On Fri, Sep 11, 2009 at 10:22 AM, Bruno Chareyre <bruno.chareyre@xxxxxxxxxxx
> wrote:

> More precisely, it is in TriaxialStressController. This engine needs to be
> assigned 6 boxes (one for each boundary). The boxes are used to define the
> surfaces (since you need a surface to define a stress).
> If you don't have 6 boxes, you need to find a workaround.
>
> The algorithm is : displacement = (stress offset) / (total box-spheres
> stiffness)
>
> Bruno
>
>
> kan a écrit :
>
>> Thanks a lot.
>>
>>
>>  On Fri, Sep 11, 2009 at 9:23 AM, Janek Kozicki <janek_listy@xxxxx>
>> wrote:
>>
>>    kan said:     (by the date of Fri, 11 Sep 2009 09:19:36 -0500)
>>
>>    > Hi, everyone,
>>    >
>>    > I am doing a simulation that I need to keep a constant stress
>>    boundary, and
>>    > the boundary may need to move at the same time.
>>    > Did anybody handle this before or how is it handled in YADE? can
>>    you give
>>    > any suggestion?
>>    > If YADE has already includes this kind of boundary, can you tell
>>    me where it
>>    > is?
>>
>>    it's defined in TriaxialTest
>>
>>    --
>>    Janek Kozicki
>>  |
>>
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