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Message #01829
Re: How to keep a constant stress boundary?
Thanks, Bruno,
I checked the code, but I still did not understand the physical meaning of
the code.
May I ask : what is the physical meaning behind the code? or what is the
mathematic of the algorithm?
how is it called ?
Thanks a lot.
yongfeng
On Fri, Sep 11, 2009 at 10:22 AM, Bruno Chareyre <bruno.chareyre@xxxxxxxxxxx
> wrote:
> More precisely, it is in TriaxialStressController. This engine needs to be
> assigned 6 boxes (one for each boundary). The boxes are used to define the
> surfaces (since you need a surface to define a stress).
> If you don't have 6 boxes, you need to find a workaround.
>
> The algorithm is : displacement = (stress offset) / (total box-spheres
> stiffness)
>
> Bruno
>
>
> kan a écrit :
>
>> Thanks a lot.
>>
>>
>> On Fri, Sep 11, 2009 at 9:23 AM, Janek Kozicki <janek_listy@xxxxx>
>> wrote:
>>
>> kan said: (by the date of Fri, 11 Sep 2009 09:19:36 -0500)
>>
>> > Hi, everyone,
>> >
>> > I am doing a simulation that I need to keep a constant stress
>> boundary, and
>> > the boundary may need to move at the same time.
>> > Did anybody handle this before or how is it handled in YADE? can
>> you give
>> > any suggestion?
>> > If YADE has already includes this kind of boundary, can you tell
>> me where it
>> > is?
>>
>> it's defined in TriaxialTest
>>
>> --
>> Janek Kozicki
>> |
>>
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>
>
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