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Re: UniaxialTest

 

On 30 April 2010 07:30, Nasibeh Moradi <nasibeh.moradi@xxxxxxxxx> wrote:

> hi Václav,
>
> I attached 2 graph, compression and tension.
> My law is symmetric and I have checked it.
>

If your law is symmetrical, what is the point to check it both in
compression and tension?


> it is very simple, and Kn and Ks are computed from
> E and v macroscopic, so it don't need to do calibration.
> I think UniaxialStrainer Engine don't work well. how do you think? you used
> it before for cpm.
> If it is necessary I can post my law too.
>
> Cheers, Nasibeh
>
>
>
> Can you post your figures?
>>
>> The reponse will be the same only as long as you stay in elastic domain
>> (no damage, plasticity etc). Assuming your law is symmetric in the
>> normal sense for tension and compression.
>>
>> BTW If you develop your own code and it is well separated from all other
>> code, don't be afraid to have in in bzr, really. It will prevent you
>> getting out of sync with then main development, we will be able to run
>> scripts where your classes are used and you might receive some useful
>> remarks on the code itself from others.
>>
>> Cheers, v.
>>
>
>
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