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Re: [Question #172345]: calculation of stress tensor and fabric tensor with rigid boundary

 

Question #172345 on Yade changed:
https://answers.launchpad.net/yade/+question/172345

    Status: Answered => Open

ceguo is still having a problem:
Hi Chiara,

Here is the output with radii increased:
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]
[(13, 4), (13, 6), (13, 5), (13, 7), (12, 0), (12, 2), (12, 3), (12, 1), (11, 2), (11, 6), (11, 7), (11, 3), (10, 0), (10, 4), (10, 5), (10, 1), (8, 0), (8, 2), (0, 2), (0, 4), (0, 1), (2, 6), (2, 3), (4, 6), (4, 5), (6, 7), (5, 7), (5, 1), (7, 3), (3, 1), (9, 1), (8, 4), (8, 6), (9, 3), (9, 7), (9, 5)]

Besides, I don't like the idea to treat walls as particles because the
walls (MASSLESS) don't have equilibrium problems. The equilibrium is
required only for particles. We can analyze the average contact number
for each particle using regular lattice. In this example with 8
particles (each has 6 contacts, 3 for p-p and 3 for p-w), and we can
calculate CN=(12x2+24x1)/8=6, because we have 12 p-p contacts which
should be counted twice and 24 p-w contacts which should be counted only
once. We can also use a much simpler case: only one particle
circumferenced  by four walls, so there are 4 p-w contacts, CN=4x1/1=4.
The model can be easily extended.

What do you think this kind of idea?

Ning

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