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[Jan Stránský <question691610@xxxxxxxxxxxxxxxxxxxxx>]

Question #691610 on Yade changed:
https://answers.launchpad.net/yade/+question/691610

    Status: Open => Answered

Jan Stránský proposed the following answer:
> ... while the data I found in other papers usually could be several kN (such as 8 kN)
> Yes, I use maximum force here to say that I really got a small magnitude of ForceN.

you really got small maximum force compared to someone else's maximum
force (at least it sounds like that). It is possible that the other
results are "crazy" and yours are OK.

Do you use the same particle sizes as the references?

> Could you please explain more about how to relate these 3 values?

(veeeeery) rough and quick estimation for transverse direction:
At = transverse area = 0.07*0.14 = 0.0098 m2
Ft = transverse force = 100kPa * At = 100e3*0.0098 = 980 N
13219 interactions, dimensions 2:1:1 => 3300 per each transverse direction, 6600 per axial direction
V = volume = 0.07*0.07*0.14 = a*a*b = 2*a*a*a
3300 interactions per volume 2*a*a*a
We need estimation of number of interactions per area 2*a*a
2*a*a = (2*a*a*a) ^ (2/3) * 2^(1/3)
3300^(2/3)*2^(1/3)=280 interactions per area 2*a*a
980 N / 280 interactions = 3.5 N

so your average value 5 N makes perfect sense in this light.

cheers
Jan

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