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[Jan Stránský <question294113@xxxxxxxxxxxxxxxxxxxxx>]

Question #294113 on Yade changed:
https://answers.launchpad.net/yade/+question/294113

    Status: Open => Answered

Jan Stránský proposed the following answer:
Hello,

Thus,in my opinion, the periodic boundary plays a same role, to some
> extent, as a plate


agree

There would be a maximum shear strain, which occurs when the lateral
> boundary becomes horizontal. So, what's the role of periodic cell?


I am not sure if I understood this point.. but "when the lateral boundary
becomes horizontal" is the extreme case when the 3d space is degenerated to
a plane. It is the maximum shear strain (also as you write) possible you
can get, resulting in zero volume of material.

The role of periodic cell is that the sample is periodic :-) In the case of
"horizontal lateral boundary", the periodic cell has no meaning, as its
volume is zero so probably you would get some very strange behavior, like
infinite number of contacts.

If I did not answer to your question or missed something, please be more
specific, possibly also sending a link to an image (pictures can't be put
directly to answers) of your problem.
cheers
Jan


2016-05-24 4:47 GMT+02:00 chuanqi liu <question294113@xxxxxxxxxxxxxxxxxxxxx>
:

> New question #294113 on Yade:
> https://answers.launchpad.net/yade/+question/294113
>
> hi, everyone.
>
> I have a similar question as proposed in "
> https://answers.launchpad.net/yade/+question/177419";.
>
> As we known, the simple shear is applied though imposing velGrad(x,y), and
> the lateral periodic boundary would rotate if velGrad(x,y) != 0. Thus,in my
> opinion, the periodic boundary plays a same role, to some extent, as a
> plate. There would be a maximum shear strain, which occurs when the lateral
> boundary becomes horizontal. So, what's the role of periodic cell?
>
> Is there any approach to apply larger shear deformation? Is there any
> similar means,  as Lees and Edwards' condition, in which the periodic cell
> keeps stationary?
>
> Thanks for help.
> Sincerely.
>
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