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[Chareyre <question295745@xxxxxxxxxxxxxxxxxxxxx>]

Question #295745 on Yade changed:
https://answers.launchpad.net/yade/+question/295745

Chareyre proposed the following answer:
 >However, when the contact is in tension, particles are not in touch and
the friction shouldn't act

It really depends on which physical situation you have in mind, which
material properties, and so on. No general rule.
If you speak of granular materials with any sort of porous cement, though,
there is no reason to assume constant fs in traction. The current equation
makes sense.
If the cement is more a Von Mises material then fs should be independent of
fn in both traction and compression, this is also possible with current
code.
Bruno

On 29 June 2016 at 18:57, VG <question295745@xxxxxxxxxxxxxxxxxxxxx>
wrote:

> Question #295745 on Yade changed:
> https://answers.launchpad.net/yade/+question/295745
>
> VG posted a new comment:
> Hello Bruno,
>
> Thanks for your response.
>
> So in the current implementation, the bending moment and twisting moment
> act on the particle but do not contribute to the breakage of bonds in
> any way.
>
> >when the contact is in tension, i.e. Fn < 0 , does the equation above
> actually reduce the value of maxFs ?
> >>Yes indeed, if cohesion and friction are combined this is what happens
>
> I am still confused about the second question.
> I understand that when the two particles are slightly overlapping, i.e. in
> compression, maxFs = shearAdhesion + Maximum friction force. In other
> words, the shear force is carried by these two different components.
> However, when the contact is in tension, particles are not in touch and the
> friction shouldn't act. In that case, why should friction interfere in the
> value of maxFs ? Shouldn't maxFs  simply be equal to shearAdhesion ?
>
> Thanks
> Varun
>
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